Résoudre les équations: 2x²+5x - 3=0; 3x² - 13x - 10=0. Merci d'avance

Bonjour
2x² + 5x - 3 = 0  
(x+3)(2x-1) = 0 
deux solutions x = -3  ou x = 1/2 
ou par 
delta = b²-4ac = (5)² - 4(2)(-3) = 25 + 24 = 49 
deux solutions
x' = (-b-Vdelta)/2a = (-5 - 7)/4 = -12/4 = -3 
x" = (-b+Vdelta)/2a = (-5+7)/4 = 2/4 = 1/2 

3x²-13x - 10 = 0 
(3x+2)(x-5) = 0 
deux solutions   x = -2/3  ou x = 5 
ou par 
delta = b² - 4ac =169 + 120 = 289  donc  Vdelta = 17
deux solutions
x ' = (-b-Vdelta)/2a = (13 - 17) / 6 = -4 / 6 = -2/3 
x" = (-b +Vdelta )/ 2a = (13 + 17)/6 = 30/6 = 5