Mathématiques

Question

heeeeeelp please? :')




heeeeeelp please? :')

1 Réponse

  • Bonjour,

    [tex]A=\dfrac{5}{3}-\dfrac{4}{3}:\dfrac{2}{15}\\\\A=\dfrac{5}{3}-\dfrac{4}{3}\times\dfrac{15}{2}\\\\A=\dfrac{5}{3}-\dfrac{60}{6}\\\\A=\dfrac{5}{3}-10\\\\A=\dfrac{5}{3}-\dfrac{30}{3}\\\\\boxed{A=-\dfrac{25}{3}}[/tex]


    [tex]B=\dfrac{5\times(10^{-4})^3\times6\times10^5}{1,5\times10^{-4}}\\\\B=\dfrac{5\times6}{1,5}\times\dfrac{(10^{-4})^3\times10^5}{10^{-4}}\\\\B=\dfrac{30}{1,5}\times\dfrac{10^{-4\times3}\times10^5}{10^{-4}}\\\\B=20\times\dfrac{10^{-12}\times10^5}{10^{-4}}\\\\B=20\times\dfrac{10^{-12+5}}{10^{-4}}\\\\B=20\times\dfrac{10^{-7}}{10^{-4}}[/tex]

    [tex]B=20\times10^{-7-(-4)}\\\\B=20\times10^{-7+4}\\\\B=20\times10^{-3}\\\\B=0,020\\\\\boxed{B=0,02}\\\\\boxed{B=2\times10^{-2}}[/tex]


    [tex]C=2\times10^{2}+10^1+10^{-1}+2\times10^{-2}\\\\C=2\times100+10+0,1+2\times0,01\\\\C=200+10+0,1+0,02\\\\\boxed{C=210,12}\\\\\boxed{C=2,1012\times10^2}[/tex]