resoudre chaque equation -1) 2(x-5) = 3x + 5 -2) -4(3 + x ) = 2x -6 -3) -3x +7 =3x - 11
Mathématiques
dialoo
Question
resoudre chaque equation
-1) 2(x-5) = 3x + 5
-2) -4(3 + x ) = 2x -6
-3) -3x +7 =3x - 11
-1) 2(x-5) = 3x + 5
-2) -4(3 + x ) = 2x -6
-3) -3x +7 =3x - 11
2 Réponse
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1. Réponse misout1
2(x-5)= 3x +5
2x -10= 3x +5
2x -10 +10 -3x= 3x +5 +10 -3x
x= 15
-4(3+x)= 2x -6
-12 -4x= 2x -6
-12 -4x +12 -2x= 2x -6 +12 -2x
-6x= 6
-6x/-6= 6/-6
x= -1
-3x +7= 3x -11
-3x +7 -7 -3x= 3x -11 -7 -3x
-6x= -18
-6x/-6= -18/-6
x= 3 -
2. Réponse katelinek54
1) 2(x-5) = 3x + 5
Développe: 2x + 10 = 3x + 5
2x = 3x + 5 - 10
2x - 3x = 5 - 10
-x = -10
x = 10
2) -4 (3+x) = 2x -6
-12 - 4x = 2x - 6
-4x = 2x -6 +12
-4x -2x = -6 + 12
-6x = 6
x = -1
3) -3x + 7 = 3x -11
-3x = 3x -11 -7
-3x - 3x = -11 -7
-6x = -18
x = 3