Mathématiques

Question

Factoriser les expressions suivantes :

A = 4xaxa - axy + ax1

B = 3 (2x+1) - (2x+1) (2x+1)

C = (3x-7) (-5x+1) - (-5x +1) (4-2x)




2 Réponse

  • A = 4xaxa - axy + ax1
    =ax(4ax-4y+1)

    B = 3 (2x+1) - (2x+1) (2x+1)
    =(2x+1)[3-(2x+1)]
    =(2x+1)(3-2x-1)
    =(2x+1)(-2x-2)
    =-2(2x+1)(x+1)

    C = (3x-7) (-5x+1) - (-5x +1) (4-2x)
    =(-5x +1)[3x-7-(4-2x)]
    =(-5x +1)(3x-7-4+2x)
    =(-5x +1)(5x-11)
  • Bonjour, 

    A = 4*a*a - a*y + a*1
    A= a(4a - y + 1)

    B = 3 (2x+1) - (2x+1) (2x+1)
    B= (2x + 1)(3 - 2x - 1)
    B= (2x + 1)(- 2x + 2)

    C = (3x-7) (-5x+1) - (-5x +1) (4-2x)
    C= (- 5x + 1)(3x - 7 - 4 + 2x)
    C= (- 5x + 1)(5x - 11)

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